Eureka Math Grade 4 Module 5 Lesson 29 Answer Key (2024)

Engage NY Eureka Math 4th Grade Module 5 Lesson 29 Answer Key

Eureka Math Grade 4 Module 5 Lesson 29 Problem Set Answer Key

Question 1.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. 2\(\frac{1}{12}\) + 1\(\frac{7}{8}\) ≈ ____40/12________

Answer:
2(1/12) + 1(7/8) = 40/12.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(1/12) + 1(7/8).
12 x 2 = 24.
1 x 8 = 8.
24 + 1/12 = 25/12.
8 + 7/8 = 15/8.
25/12 + 15/8 = 40/12.

b. 1\(\frac{11}{12}\) + 5\(\frac{3}{4}\) ≈ ____46/4_________

Answer:
1(11/12) + 5(3/4) = 46/4.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
1(11/12) + 5(3/4).
12 x 1 = 12.
5 x 4 = 20.
12 + 11/12 = 23/12.
20 + 3/4 = 23/4.
23/12 + 23/4 = 46/4.

c. 8\(\frac{7}{8}\) – 2\(\frac{1}{9}\) ≈ ____52/9________

Answer:
8(7/8) – 2(1/9) = 52/9.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
8(7/8) – 2(1/9).
8 x 8 = 64.
2 x 9 = 18.
64 + 7/8 = 71/8.
18 + 1/9 = 19/9.
71/8 – 19/9 = 52/9.

d. 6\(\frac{1}{8}\) – 2\(\frac{1}{12}\) ≈ __________

Answer:
6(1/8) – 2(1/12) = 24/12.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
6(1/8) – 2(1/12).
6 x 8 = 48.
2 x 12 = 24.
48 + 1/8 = 49/8.
24 + 1/12 = 25/12.
49/8 – 25/12 = 24/12.

e. 3\(\frac{3}{8}\) + 5\(\frac{1}{9}\) ≈ _____73/9______

Answer:
3(3/8) + 5(1/9) = 73/9.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
3(3/8) + 5(1/9).
8 x 3 = 24.
5 x 9 = 45.
24 + 3/8 = 27/8.
45 + 1/9 = 46/9.
27/8 + 46/9 = 73/9.

Question 2.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. \(\frac{16}{5}\) + \(\frac{11}{4}\) ≈ ______

Answer:
16/5 + 11/4 = 6.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
16/5 + 11/4.
16/5 = 3.2.
11/4 = 2.75.
3.2 + 2.75 = 5.95.
16/5 + 11/4 = 5.95.

b. \(\frac{17}{3}\) – \(\frac{15}{7}\) ≈ _______

Answer:
17/3 + 15/7 = 8.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
17/3 + 15/7.
17/3 = 5.6.
15/7 = 2.14.
5.6 + 2.14 = 7.74.
17/3 + 15/7 = 7.74.

c. \(\frac{59}{10}\) + \(\frac{26}{10}\) ≈ _______

Answer:
59/10 + 26/10 = 8.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
59/10 + 26/10.
59/10 = 5.9.
26/10 = 2.6.
5.9 + 2.6 = 8.5.
59/10 + 26/10 = 8.

Question 3.
Montoya’s estimate for 8\(\frac{5}{8}\) – 2\(\frac{1}{3}\) was 7. Julio’s estimate was 6\(\frac{1}{2}\). Whose estimate do you think is closer to the actual difference? Explain.

Answer:
8(5/8) -2(1/3) = 62/5.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
8(5/8) – 2(1/3).
8 x 8 = 64.
2 x 3 = 6.
64 + 5/8 = 69/8.
6 + 1/3 = 7/3.
69/8 – 7/3 = 62/5.

Question 4.
Use benchmark numbers or mental math to estimate the sum or difference.
a. 14\(\frac{3}{4}\) + 29\(\frac{11}{12}\)

Answer:
14(3/4) + 29(11/12) = 418/12.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
14(3/4) + 29(11/12).
14 x 4 = 56.
29 x 12 = 348.
56 + 3/4 = 59/4.
348 + 11/12 = 359/12.
59/4 + 359/12 = 418/12.

b. 3\(\frac{5}{12}\) + 54\(\frac{5}{8}\)

Answer:
3(5/12) + 54(5/8) = 478/12.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
3(5/12) + 54(5/8).
12 x 3 = 36.
54 x 8 = 432.
36 + 5/12 = 41/12.
432 + 5/8 = 437/8.
41/12 + 437/8 = 478/12.

c. 17\(\frac{4}{5}\) – 8\(\frac{7}{12}\)

Answer:
17(4/5) – 8(7/12) = 192/60.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
17(4/5) – 8(7/12).
17 x 5 = 85.
12 x 8 = 96.
85 + 4/5 = 89/5.
96 + 7/12 = 103/12.
89/5 + 103/12 = 192/60.

d. \(\frac{65}{8}\) – \(\frac{37}{6}\)

Answer:
65/8 – 37/6 = 4.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
65/8 – 37/6.
65/8 = 8.1.
37/6 = 6.1.
8.1 – 6.1 = 4.1.
65/8 – 37/6 = 4.1.

Eureka Math Grade 4 Module 5 Lesson 29 Exit Ticket Answer Key

Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
Question 1.
2\(\frac{9}{10}\) + 2\(\frac{1}{4}\) ≈ _________

Answer:
2(9/10) + 2(1/4) = 38/40.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(9/10) + 2(1/4).
2 x 10 = 20.
2 x 4 = 8.
20 + 9/10 = 29/10.
8 + 1/4 = 9/4.
29/10 + 9/4 = 38/40.

Question 2.
11\(\frac{8}{9}\) – 3\(\frac{3}{8}\) ≈ _________

Answer:
11(8/9) – 3(3/8) = 80/72.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
11(8/9) – 3(3/8).
11 x 9 = 99.
3 x 8 = 24.
99 + 8/9 = 107/9.
24 + 3/8 = 27/8.
107/9 – 27/8 = 80/72.

Eureka Math Grade 4 Module 5 Lesson 29 Homework Answer Key

Question 1.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. 3\(\frac{1}{10}\) + 1\(\frac{3}{4}\) ≈ ___________

Answer:
3(1/10) + 1(3/4) = 38/40.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
3(1/10) + 1(3/4).
10 x 3 = 30.
1 x 4 = 4.
30 + 1/10 = 31/10.
4 + 3/4 = 7/4.
31/10 + 7/4 = 38/40.

b. 2\(\frac{9}{10}\) + 4\(\frac{4}{5}\) ≈ __________

Answer:
2(9/10) + 4(4/5) = 53/50.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(9/10) + 4(4/5).
2 x 10 = 20.
5 x 4 = 20.
20 + 9/10 = 29/10.
20 + 4/5 = 24/5.
29/10 + 24/5 = 53/50.

c. 9\(\frac{9}{10}\) – 5\(\frac{1}{5}\) ≈ __________

Answer:
9(9/10) – 5(1/5) = 73/5.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
9(9/10) – 5(1/5).
9 x 10 = 90.
5 x 5 = 25.
90 + 9/10 = 99/10.
25 + 1/5 = 26/5.
99/10 – 26/5 = 73/5.

d. 4\(\frac{1}{9}\) – 1\(\frac{1}{10}\) ≈ __________

Answer:
4(1/9) – 1(1/10) = 48/10.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
4(1/9) – 1(1/10).
9 x 4 = 36.
1 x 10 = 10.
36 + 1/9 = 37/9.
10 + 1/10 = 11/10.
37/9 + 11/10 = 48/10.

e. 6\(\frac{3}{12}\) + 5\(\frac{1}{9}\) ≈ _______

Answer:
6(3/12) + 5(1/9) = 121/9.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
6(3/12) + 5(1/9).
6 x 12 = 72.
5 x 9 = 45.
72 + 3/12 = 75/12.
45 + 1/9 = 46/9.
75/12 + 46/9 = 121/9.

Question 2.
Estimate each sum or difference to the nearest half or whole number by rounding. Explain your estimate using words or a number line.
a. \(\frac{16}{3}\) + \(\frac{17}{8}\) ≈ __________

Answer:
16/3 + 17/8 = 7.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
16/3 + 17/8.
16/3 = 5.3.
17/8 = 2.1.
5.3 + 2.1 = 7.4.
16/3 + 17/8 = 7.

b. \(\frac{17}{3}\) – \(\frac{15}{4}\) ≈ __________

Answer:
17/3 – 15/4 = 9.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
17/3 – 15/4.
17/3 = 5.6.
15/4 = 3.7.
5.6 + 3.7 = 9.3.
15/4 + 17/3 = 9.

c. \(\frac{57}{8}\) + \(\frac{26}{8}\) ≈ __________

Answer:
57/8 + 26/8 = 10.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
57/8 + 26/8.
57/8 = 7.1.
26/8 = 3.2.
7.1 + 3.2 = 10.3.
57/8 + 26/8 = 10.

Question 3.
Gina’s estimate for 7\(\frac{5}{8}\) – 2\(\frac{1}{2}\) was 5. Dominick’s estimate was 5\(\frac{1}{2}\). Whose estimate do you think is closer to the actual difference? Explain.

Answer:
7(5/8) – 2(1/2) = 56/4.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
7(5/8) – 2(1/2).
8 x 7 = 56.
2 x 2 = 4.
56 + 5/8 = 61/8.
4 + 1/2 = 5/2.
61/8 – 5/2 = 56/4.

Question 4.
Use benchmark numbers or mental math to estimate the sum or difference.
a. 10\(\frac{3}{4}\) + 12\(\frac{11}{12}\)

Answer:
10(3/4) + 12(11/12) = 199/3.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
10(3/4) + 12(11/12).
10 x 4 = 40.
12 x 12 = 144.
40 + 3/4 = 43/4.
144 + 11/12 = 156/12.
43/4 + 156/12 = 199/3.

b. 2\(\frac{7}{10}\) + 23\(\frac{3}{8}\)

Answer:
2(7/10) + 23(3/8) = 214/80.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
2(7/10) + 23(3/8).
2 x 10 = 20.
23 x 8 = 184.
20 + 7/10 = 27/10.
184 + 3/8 = 187/8.
27/10 + 187/8 = 214/80.

c. 15\(\frac{9}{12}\) – 8\(\frac{11}{12}\)

Answer:
15(9/12) – 8(11/12) = 82/12.

Explanation:
In the above-given question,
given that,
Estimate each difference to the nearest half.
15(9/12) – 8(11/12).
15 x 12 = 180.
8 x 12 = 96.
180 + 9/12 = 189/12.
96 + 11/12 = 107/12.
189/12 – 107/12 = 82/12.

d. \(\frac{56}{7}\) – \(\frac{31}{8}\)

Answer:
56/7 – 31/8 = 4.2.

Explanation:
In the above-given question,
given that,
Estimate each sum to the nearest half.
56/7 – 31/8.
56/7 = 8.
31/8 = 3.8.
8 – 3.8 = 4.2.
56/7 – 31/8 = 4.2.

Eureka Math Grade 4 Module 5 Lesson 29 Answer Key (2024)

FAQs

What grade does Eureka math go up to? ›

Eureka Math® is a holistic Prekindergarten through Grade 12 curriculum that carefully sequences mathematical progressions in expertly crafted modules, making math a joy to teach and learn. We provide in-depth professional development, learning materials, and a community of support.

What are the four core components of a Eureka Math TEKS lesson? ›

Lesson Components

Within every lesson, students experience the same four core components: - Fluency Practice, - Application Problem, - Concept Development (which includes a Problem Set), and - Student Debrief (which includes an Exit Ticket).

Is Eureka Math a curriculum? ›

An Elementary, Middle, And High School Math Curriculum. Eureka Math® is a math program designed to advance equity in the math classroom by helping students build enduring math knowledge.

What is the purpose of the concept development in Eureka math? ›

The concept development is generally comprised of carefully sequenced problems centered within a specific topic to begin developing mastery via gradual increases in complexity.

What is the hardest math grade? ›

Generally speaking, the most rigorous math courses in high school include Advanced Placement (AP) Calculus AB and BC, AP Statistics, and for some, Multivariable Calculus (which might be offered at your school or at a local college).

What is the highest math class ever? ›

Math 55 is a two-semester freshman undergraduate mathematics course at Harvard University founded by Lynn Loomis and Shlomo Sternberg. The official titles of the course are Studies in Algebra and Group Theory (Math 55a) and Studies in Real and Complex Analysis (Math 55b).

Is Eureka Math good or bad? ›

Is Eureka Math a good curriculum? The answer to this question depends on the target audience. If you're a teacher in a public school who needs to cover State Standards and your goal is merely to prepare students for State tests, then Eureka may be a good curriculum for you.

Is Eureka Math no longer free? ›

Anyone can download the entire PK–12 Eureka Math curriculum, along with a variety of instructional materials and support resources, for free. Some materials, such as our printed workbooks, Eureka Digital Suite, Affirm, Eureka Math Equip, and Eureka Math in Sync must be purchased.

What is the Eureka Math curriculum for 4th grade? ›

The Eureka Math Curriculum Study Guide, Grade 4 provides an overview of all of the Grade 4 modules, including Place Value, Rounding, and Algorithms for Addition and Subtraction; Unit Conversions and Problem Solving with Metric Measurement; Multi-Digit Multiplication and Division; Angle Measure and Plane Figures; ...

How long does an Eureka math lesson take? ›

Eureka Math is 1 hour for all grade levels (except in Kindergarten lessons are 50 minutes). We have always designed our elementary day with 1 hour dedicated to mathematics instruction.

Is Eureka Math scripted? ›

Eureka Math is not intended to be followed as a script, instead as a guide to offer support to teachers in the classroom. For example, the “vignettes” of teacher-student interactions included in Eureka Math are exemplars of instructional situations provided by the teachers who have crafted our curricula.

How to make Eureka math engaging? ›

Here are some tips to get through it, primarily if you teach primary learners.
  1. Fluency Activities. Every Eureka math lesson comes with fluency activities. ...
  2. Concept Development. Concept development is your lesson or instructional focus for the day. ...
  3. Debrief. ...
  4. Additional Websites. ...
  5. Small Math Groups. ...
  6. Math Centers.
Nov 28, 2022

What is the highest level of math in 9th grade? ›

9th grade math usually focuses on Algebra I, but can include other advanced mathematics such as Geometry, Algebra II, Pre-Calculus or Trigonometry.

What is the hardest math in 5th grade? ›

Some of the hardest math problems for fifth graders involve multiplying: multiplying using square models, multiplying fractions and whole numbers using expanded form, and multiplying fractions using number lines.

What is the Eureka math curriculum for 4th grade? ›

The Eureka Math Curriculum Study Guide, Grade 4 provides an overview of all of the Grade 4 modules, including Place Value, Rounding, and Algorithms for Addition and Subtraction; Unit Conversions and Problem Solving with Metric Measurement; Multi-Digit Multiplication and Division; Angle Measure and Plane Figures; ...

Is geometry in 8th grade advanced? ›

8th-grade math typically includes Number System, Linear Equations, Fractions, and Decimals. Students are also introduced to some advanced topics like Pre-Algebra, Algebra I, and Geometry. 8th grade is the third year of middle school.

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